问答题 (南京大学2008年考研试题)E.Coli cells are growing in a medium containing lactose but no glucose,indicate whether each of the following changes or conditions would increase,decrease,or not change the expression of the lac opern.It may be helpful to draw a model depicting what is happening in each situation. (a)addition of a high concentration of glucose (b)a mutation that prevents dissociation ofthe Lac repressor form the operator (c)a mutation that completely inactivates β-galactosidase (d)a mutation that completely inactivates galactosied permease (e)a mutation that prevents binding of CRP to its binding site near the lac promoter
【正确答案】正确答案: (a)随着葡萄糖浓度增加,cAMP含量减少,低浓度的cAMP使C反应蛋白不能绑定来帮助RNA聚合酶结合到启动子区,所以乳糖操纵子的表达降低。 (b)这个突变将使乳糖阻遏物长期不变地绑定DNA,并长期不变地关闭乳糖操纵子,所以乳糖操纵子的表达降低。 (c)如果β-半乳糖苷酶没有活性,异乳糖则不能形成,并且乳糖操纵子不能被开启,所以乳糖操纵子的表达降低。 (d)如果能在细胞中得到半乳糖而异乳糖不能形成,则乳糖操纵子不能被开启,所以乳糖操纵子的表达降低。 (e)C反应蛋白不能绑定来帮助RNA聚合酶结合到启动子区,所以乳糖操纵子的表达降低。
【答案解析】