选择题   设A是4阶方阵,则下列线性方程组是同解方程组的是______
 
【正确答案】 D
【答案解析】显然,由AiX=0,两边左乘以A,得Ai+1X=0,i=1,2,3,4,四个选项均成立. 反之,若Ai+1X=0,是否有AiX=0. 对A,取,A2=0,取X=[0,0,1,1]T,则A2X=0x=0,但AX=,故A不是同解方程组. 对B,取,,A3=0,取X=[0,0,0,1]T,则A3X=0,但,故B不是同解方程组. 对C,取,,A4=0,取X=[0,0,0,1]T,则A4X=0,但,故C不是同解方程组. 由排除法知,应选择D. 对于D:易知A4X=0A5X=0,要证A5X=0A4X=0,用反证法,设A5X=0,而A4X≠0,因5个四维向量X,AX,A2X,A3X,A4X必线性相关,存在不全为零的数k0,k1,k2,k3,k4使得 k0X+k1AX+k2A2X+k3A3X+k4A4X=0. (*) 对(*)式两边左乘A4,得 k0A4X+k1A5X+k2A6X+k3A7X+k4A8X=0k0A4X=0, 又A4X≠0得k0=0,将k0=0代入(*)式,类似的再两边左乘A3,可得k1=0,同理可得k2=k3=k4=0,这和X,AX,A2X,A3X,A4X线性相关矛盾,故A5X=0A4X=0.(一般地,当A为n阶方阵时,有An+1X=0AnX=0) 故A是四阶方阵时,A4X=0和A5X=0是同解方程组.