【答案解析】解析:(1)短路点处

(2)各序电流相等,各序电压之和等于零,正序、负序、零序网络互相串联。 (3)根据已知各元件的正、负序参数,则该系统的复合序网中

=1.0/0° x
1∑
=x"
d
+x
T
+x
L(1)
=0.289+0.21+0.182=0.681 x
2∑
=x
(2)
+x
T
+x
L(2)
=0.289+0.21+0.182=0.681 x
0∑
=x
T
+3x
P
+3x
L(1)
=0.21+3×0.348+3×0.182=1.8 (4)短路点电流和电压的各序分量为:
