填空题 12.∫01dy∫0y2ycos(1-x)2dx=_______．
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【正确答案】 1、    
【答案解析】∫01dy∫0y2ycos(1-x)2dx=∫01cos(1-x)2dxydy
=∫01(1-x)cos(1-x)2dx=∫01cos(1-x)2d(1-x)2
=∫01costdt=∫01costdt=