单选题 Working alone,a small pump takes twice as long as a large pump takes to fill an empty tank.Working together at their respective constant rates,the pumps can fill the tank in 6 hours.How many hours would it take the small pump to fill the tank working alone?
A. 8 B. 9 C. 12
D. 15 E. 18

【正确答案】 E
【答案解析】单独工作时,一个小水泵充满一个空水箱所花的时间是大水泵的两倍。两个水泵保持其各自通常的速度共同工作时,共需花6个小时灌满水箱。若小水泵单独工作时,需花多长时间才能灌满水箱?
设小水泵需花x小时灌满水箱,则大小泵需花[*]小时灌满小箱,由题意可得:
[*]