根据《建筑抗震设计规范》(GB 50011—2001)第5.1.4条第5.1.5条计算
amax=1.20,Tg=0.40s,ζ=0.08
5Tg=5×0.4=2.0s>1.9s,a在曲线下降段
γ=0.9+(0.05-ζ)/(0.5+5ζ)
=0.9+(0.05-0.08)/(0.5+5×0.08)
=0.87
η2=1+(0.05-ζ)/(0.06+1.7ζ)=0.85
a=