ea1=γhKa=qKa=10×tan2(45°-34°/2)=2.8kPa
ea2=γ(H+h)Ka=(q+λH)tan2(45°-ψ/2)
=(10+19×6×tan(45°-34°/2)=35.1kPa
Ea=(ea1+ea2)H/2=(2.8+35.1)×6/2=113.8kN/m
土压力作用点Z(距坑底距离)