图4-67所示平面刚性直角曲杆的支撑、尺寸与载荷均已知,且F P a>m。B处插入端约束的全部约束力各为( )。
F Bx =0,F By =F P (↑),力偶m B =F P a(↓)
F Bx =0,F By =F P (↑),力偶m B =0
F Bx =0,F By =F P (↑),力偶m B =F P a-m(↓)
F Bx =0,F By =F P (↑),力偶m B =F P b-m(↓)
解析:对整体列出平面任意力系的三个平衡方程即可求出B处的约束力。