【正确答案】
A
【答案解析】[解析]
(1)覆时旋转点位置x0。
因ι1=240<2.2h=396mm,故
x0=0.13ι1=0.13×240=31(mm)
(2)倾覆力矩
Mov=1.2×4.5×0.8×2.0×(0.8/2+0.031)+1.4×1×(0.8+0.031)
=4.89(kN·m)
(3)抗倾覆力矩
MR=0.8×{[3.22×3.5-(1.52+0.752)]0.24×19(0.24/2-0.031)
+(102.8+0.24+0.18×3.5×25)(0.24/2-0.031)}
=5.00(kN·m)