【答案解析】根据《建筑边坡工程技术规范》6.2.3条:q=0,α=90°,β=0°,φ=24°,δ=16°,则:
η=2c/γH=

=1.0
K
q=1+

=1.0
由规范式(6.2.3-2):

K
q[sin(α+β)sin(α-δ)+sin(φ+δ)sin(φ-β)]
=1.0×[sin90°.sin(90°-16°)+sin(24°+16°).sin(24°-0)]=0.700
2ηsinαcosφcos(α+β-φ-δ)
=2×1.0×sin90°.cos24°.cos(90°+0-24°-16°)=1.174

=2×1.149×1.238=2.845
故:K
a=1.704×(0.700+2×1.174-2.845)=0.346
E
a=1/2γH
2K
a=
