【答案解析】解析:《岩土工程勘察规范》(GB 50021--2001)(2009年版)第5.2.8条条文说明。 ψ
1
=cos(θ
1
—θ
2
)—sin(θ
1
—θ
2
)tanφ =cos(30°一25°)一sin(30°一25°)tan16° =0.971 ψ
2
=cos(θ
2
一θ
3
)一sin(θ
2
一θ
3
)tanφ =cos(25°+5°)一sin(25°+5°)tan16° =0.723 R
1
=G
1
cosθ
1
tanφ
1
)1+c
1
L
1
=19×54.5×cos30°tan19°+10×16=468.78 T
1
=G
1
sinθ
1
=19×54.5×sin30°=517.75 R
2
=G
2
cosθ
2
tanφ
2
+c
2
L
2
=(19×43.0+9.5×27.5)×cos25°tan16°+7×12 =364.22 T
2
=G
2
sinθ
2
=(19×43.0+9.5×27.5)×sin25°=455.69 R
3
=G
3
cosθ
3
tanφ
3
+c
3
L
3
=(9.5×20.0)×cos5°tan16°+7×8=110.27 T
3
=一G
2
sinθ
2
=一(9.5×20.0)×sin5°=一16.56
