解答题 17.设u=f(x+y,x2+y2),其中f二阶连续可偏导,求
【正确答案】=f1'+2xf2'.
=f1’+2yf2’,
=f11"+2xf12"+2f2’+2x(f21"+2xf22")=f11"+4xfz2"+4x2f22"+2f2’,
=f11"+2yf12"+2f2’+2y(f21"+2yf22")=f11"+4yf12"+4y2f22"+2f2’,
【答案解析】