问答题
一对啮合的标准直齿圆柱齿轮(α=20°，
=1，
=1，
【正确答案】d1=mz1=4mm×20=80mm
d2=mz2=4mm×40=160mm
da1=m(z1+2)=4mm×(20+2)=88mm
da2=m(z2+2)=4mm×(40+2)=168mm
S=πm/2=3.14×4mm/2=6.28mm
a=(d1+d2)/2=(80mm+160mm)/2=120mm
d2=mz2=4mm×40=160mm
da1=m(z1+2)=4mm×(20+2)=88mm
da2=m(z2+2)=4mm×(40+2)=168mm
S=πm/2=3.14×4mm/2=6.28mm
a=(d1+d2)/2=(80mm+160mm)/2=120mm
【答案解析】