问答题 设y=y(x)由y 3 +(x+1)y+x 2 =0确定,且y(0)=0.
【正确答案】
【答案解析】[解] 由y 3 +(x+1)y+x 2 =0.

3y 2 y"+y+(x+1)y"+2x=0,
由x=0,y(0)=0,得y"(0)=0.

6yy "2 +3y 2 y " +y " +y " +(x+1)y " +2=0,
由x=0,y(0)=0,y"(0)=0,得y"(0)=-2.