问答题 对上题再进行改进,使输入文件名和读文件内容的两类异常都能处理。请在横线处填上适当的子句,使其能捕获异常并正确执行。 import java.io.*; public class BException{ public static void main(String[]args){ //获得文件名 BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in)); System.out.print("Filename:"); String s=null; try{ s=stdin.readLine(); }catch(OIException e){ System.err.println("Cannot read input"); System.exit(0); } BufferedReader filein=null; //为处理组织文件流 try{ Filein=new BufferedReader(new FileReader(s)); } catch(FileNotFoundException e){ System.err.println(s+":cannot be opened for reading"); System.exit(0); } try{ int numerator=Integer.parseInt(filein.readLine()); //提取值和计算商 int denominator=Integer.parseInt(filein.readLine()); int quotient=numerator/denominator; System.out.println(); System.out.println(numerator+"/"+denominator+"="+quotient); }______{ System.err.println(s+":unable to read values"); System.exit(0); } return; } }
【正确答案】填入catch(IOException e)
【答案解析】