的值大于零的概率等于
=X
1
X
4
—X
2
X
3
,则p应使P{△>0}=P{X
1
X
4
—X
2
X
3
>0}=P{X
1
X
4
>X
2
X
3
}=
,因为X
i
仅能取1或0,且相互独立,故事件{X
1
X
4
>X
2
X
3
}={X
1
X
4
=1,X
2
X
3
=0},所 以
=P{X
1
=1,X
4
=1,X
2
=0,X
3
=0}+P{X
1
=1,X
4
=1,X
2
=o,X
3
=1}+P{X
1
=1,X
4
=1,X
2
=1,X
3
=0}=p
2
(1一p)
2
+p
3
(1一p) +p
3
(1一p)=p
2
(1一p
2
)=p
2
一p
4
,则 p
4
一p
2
+
