【答案解析】 1.lim
f d =T
-1 lim
c =LT
-1 lim
K =1 lim
f 0 =T
-1 lim
v =LT
-1 lim
α =1
2.
K =10
-9 3.标准值

=(106.1+102.4+100.2+105.5+108.2+97.7+104.6+93.8+98.3+101.4)/10 =101.82m/s 被检测速仪平均值

=(101.9+100.2+98.3+101.6+103.4+96.9+101.6+95.7+97.2+100.6)/10 =99.74m/s
s =

=2.57m/s,所以被检测速仪的重复性为2.57m/s,示值误差为99.74-101.82=-2.08m/s 4.假设被检测速仪速度测量值中由发射频率引起的不确定度分量服从均匀分布,则区间半宽度为100MHz,则
u =100/
