问答题
设g
1
(x)g
2
(x)|f
1
(x)f
2
(x)f
1
(x)|g
1
(x)，f
1
(x)≠0，则g
2
(x)|f
2
(x)．
设g
1
(x)g
2
(x)|f
1
(x)f
2
(x)且g
1
(x)|f
1
(x)，则g
2
(x)|f
2
(x)?
【正确答案】
[例] 设g
1
(x)=x-1，g
2
(x)=(x+1)(x
2
-4)，f
1
(x)=(x-1)(x-2)，f
2
(x)=(x+1)(x+2)．显然g
1
(x)g
2
(x)|f
1
(x)f
2
(x)且g
1
(x)|f
1
(x)，但g
2
(x)+f
2
(x)．
【答案解析】
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