问答题 以K9玻璃(nD=1.5163，nF=1.5220， nC=1.5139)和F4玻璃(nD=1.6199，nF=1.632l，nC=1.6150)组合成消初级球差和近轴区域消除位置色差的胶合透镜组，合成焦距为100mm，试求各面曲率半径(设l=∞)，同时求∑SⅠ和∑SⅡ值。
【正确答案】r1=45.88mm，r2=-43.26mm，r3=-542.55mm。
   
1
2
3
l
134.74306
182.86501
-r
-43.26
-542.55
l-r
178.00306
725.4150
×u
5
0.037107663
0.027342573
÷r
45.88
-43.26
-542.55
i
0.10897995
-0.15268788
-0.036558313
×n/n'
1/1.5163
1.5163/1.6199
1.0199/1
i'
0.071872286
-0.14292279
-0.059220811
÷u'
0.037107663
0.027342573
0.05000507
i'/u'
1.9368583
-5.2271155
-1.18429613
+1
1
1
1
i'/u'+1
2.9368583
-4.2271155
0.18429613
×r
45.88
-43.26
-542.55
1
2
3
l'
134.74306
182.86501
99.98986
u
0
0.037107663
0.027342573
+i
0.10897995
-0.15268788
-0.036558313
u+i
0.10897995
-0.115580217
-0.00921574
-i'
0.071872286
-0.14292279
-0.059220811
u'
0.037107663
0.027342573
0.05000507
lu
5
5
5
÷u'
0.037107663
0.0273422573
0.05000507
l'
134.74306
182.86501
99.98986
-d
0
0
l
134.74306
182.86501
luni
0.54489975
-1.15760316
-0.296104056
×(i-i')
0.037107664
-0.00976509
0.022662498
×(i'-u)
0.071872286
-0.180030453
-0.086563384
SⅠ
0.001453254
-0.002035082
0.000580879
×iz/i
0.45879999
-0.21596344
-0.84429771
SⅡ
0.000666752
0.00439503
-0.000490434
sum_{1}^{3}S_{Ⅰ}=-0.000000949
sum_{1}^{3}S_{Ⅱ}=0.000615821
【答案解析】