【正确答案】正确答案:(I)设该投篮人投篮次数为X,投篮得分为Y;每次投篮命中率为p(0<p<1),则X的概 率分布为 P{X=1}=p, P{X=2}=pq, P{X=3}=q
2
, EX=p+2pq+3q
2
=p+2p(1一p)+3(1一p)
2
=p
2
一3p+3. 依题意 p
2
一3p+3=1.56, 即 p
2
一3p+1.44=0. 解得p=0.6(p=2.4不合题意,舍去). (Ⅱ)Y可以取0,1,2,3四个可能值,且 P{Y=0}=q
3
=0.4
3
=0.064, P{Y=1}=pq2=O.6×O.4。=0.096, P{Y=2}=pq=0.6×0.4=0.24, P{Y=3}=p=0.6, 于是
