问答题
考虑常微分方程初值问题
取正整数n，记
,x
i
=a+ih，0≤i≤n．分析求解公式y
i+1
=y
i
+
取正整数n，记
,x
i
=a+ih，0≤i≤n．分析求解公式y
i+1
=y
i
+
【正确答案】正确答案：R
i+1
=y(x
i+1
)-y(x
i
) -
[5f(x
i+1
,y(x
i+1
)+8f(x
i
,y(x
i
))-f(x
i-1
,y(x
i-1
))]=y(x
i+1
)-y(x
i
)-
[5f(x
i+1
,y(x
i+1
)+8f(x
i
,y(x
i
))-f(x
i-1
,y(x
i-1
))]=y(x
i+1
)-y(x
i
)-
【答案解析】