问答题 Chlorine gas can be prepared by adding dilute HCl(aq) dropwise onto potassium permanganate crystals，KMnO4. The KMnO4 is reduced to Mn2+(aq). What volume (in liters) of 1.50mol·L-1 HCl(aq) is required to react with 12.0g KMnO4?
【正确答案】2KMnO4+16HCl===2MnCl2+5Cl2↑+8H2O+2KCl
   n(HCl)=8n(KMnO4)=8m(KMnO4)/M(KMnO4)
   =8×12.0g/]58g·mol-1
   =0.608mol
   So：  V(HCl)=n(HCl)/c(HCl)
   =0.608mol/1.50mol·L-1
   =0.405L
【答案解析】