3c-2a=0.4. ② 由P{X≤0|Y≥2}
3a-5c=-0.7. ③ 联立①,②,③,解方程组
及Z=X+Y,可知Z的取值为0,1,2,3,4.由于 P{Z=0}=P{X=-1,Y=1}=0.1, P{Z=1}=P{X=0,Y=1}+P{X=-1,Y=2}=0.1+0.1=0.2, P{Z=2}=P{X=0,Y=2}+P{X=-1,Y=3}+P{X=1,Y=1} =0.2+0.2=0.4. P{Z=3}=P{X=0,Y=3}+P{X=1,Y=2}=0.1, P{Z=4}=P{X=1,Y=3}=0.2, 从而得Z的概率分布为
