(i=1,2,3,4),求X=
=X
1
X
4
-X
2
X
3
,令U=X
1
X
4
,V=X
2
X
3
,且U,V独立同分布.P(U=1)=P(X
1
=1,X
4
=1)=0.16,P(U=0)=0.84,X的可能取值为-1,0,1. P(X=-1)=P(U=0,V=1)=P(U=0)P(V=1)=0.84×0.16=0.134 4, P(X=1)=P(U=1,V=0)=P(U=1)P(V=0)=0.16×0.84=0.1 34 4, P(X=0)=1-2×0.134 4=0.731 2,于是
