【正确答案】正确答案:根据初等矩阵的运算性质,有 E
3
(2(k))=E(2(k
3
)),E
4
(21(-2))=E(21(-8)), E
-1
(2(k
3
))=E(2(k
-3
)),E
-1
(21(-8))=E(21(8)), 从而有 B=[E
3
(2(k))]
-1
A[E
4
(21(-2))]
-1
=E(2(k
-3
))AE(21(8))

【答案解析】解析:本题计算过程中用到初等矩阵的幂运算和逆运算的性质,即 E
m
(i(k))=E(i(k
m
)),E
m
(ij(k))=E(ij(mk)), E
-1
(i(k))=E(i(k
-1
)),E
-1
(ij(k))=E(ij(-k)).