【正确答案】正确答案:直接应用F(x)=P{X≤x},F
Y
(y)=P{F(X)≤y}求解.
(Ⅱ)令Y=F(X),则由0≤F(x)≤1及F(x)为x的单调不减连续 函数知(如图2.1),当Y<0时F
Y
(y)=0;当y≥1时,F
Y
(y)=1;当0≤y<
时, F
Y
(y)=P{F(X)≤y}=P{F(X)≤0}+P{0<F(X)≤y}
当
≤y<1时, F
Y
(y)=P{F(X)≤y} =P{F(X)≤0}+P{0<F(X)≤
<F(X)≤y} =0+P{0<X<1}+P{1<X≤F
-1
(y)}
综上得