填空题 [说明] 用输入/输出写一个程序,让用户输入一些姓名和电话号码。每一个姓名和号码将加在文件里。用户通过点“Done”按钮来告诉系统整个列表已输入完毕。 如果用户输入完整的列表,程序将创建一个输出文件并显示或打印出来。格式如:555,1212,Tom 123-456-7890,Peggy L.234-5678,Marc 234-5678,Ron 876-4321,Beth&Brian 33.1.42.45.70,Jean-Marc。 [Java 代码] import java. io.*; class Phones { statlc FileOutputStream fos; public static final int lineLength =81; public static void main (String args []) throws IOExeption { byte [] phone=new byte [lineLength]; byte [] name=new byte [lineLength]; int i; try { fos= new FileOutputStream ("phone. numbers"); } catch (FileNotFoundException e) while (true) { {{U}}(1) {{/U}}("Enter a name (enter 'done' to quit)"); {{U}}(2) {{/U}} (name); if ("done". equalsIgnoteCase (new String (name,0,0,4))) { break; } System.err.println ("Enter the phone number"); readLine (phone); for (int i=0;phone [i]!=0;i++) { {{U}}(3) {{/U}}; } fos.write (','); for (int i=0{{U}} (4) {{/U}};i++) { fos. write (name [i]); } fos. write ('/n'); } fos. close(); } private static void readLine (byte line []) throws IOException { int i=0,b=0; while ((i<{{U}} (5) {{/U}})&& ((b=System.in.read ())!='/n')) { line[i++] = ( byte ) b; } line[i]= ( byte ) 0; } }
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【正确答案】 1、(1)System. err. println (2) readLine    
【答案解析】(3) fos. write(phone[i]) (4) name[i]!=0 (5) lineLength-1