问答题
一对蜗杆蜗轮,z1=1,z2=82,m=2mm,γ=5°06'08",α=20°,试求它们的分度圆弦齿厚和弦齿高。
【正确答案】(1)Sn1≈Sn=(πmcosγ)/2=(3.1416×2×cos5°06'08")/2mm=3.1291mm≈3.13mm
hn1≈m=2mm
由于S2/2=(πm/2)2,d(2/2)=(mz2)2,S=πm/2则
(2)Sn2=S{1-(S2/2)/6d(2/2)}cosγ
=πm/2{1-(πm/2)2/6(mz2)2}cosγ
=(3.1416×2)/2{1-(3.1416×2/2)2/6(2×82)2}cos5°06'08"mm
=3.1288min≈3.13mm
hn2=m+{(s2/2)cos4γ}/4d2
=2+(3.1416×2/2)2cos5°06'08"/4(2×82)mm
=2.0148mm≈2.01mm
Sn1=3.13mm,hn1=2mm,Sn2=3.13mm,hn2=2.01mm
【答案解析】