P{X
0
=1,X
2
=1}=P(A
0
A
2
). 必要性.设随机变量X
1
和X
2
独立,则P(A
1
A
2
)=P{X
1
=1,X
2
=1}=P{X
1
=1}P{X
2
=1}=P(A
1
)P(A
2
),从而事件A
1
和A
1
相互独立. 充分性.设事件A
1
和A
1
相互独立,则
也都独立,故 P{X
1
=0,X
2
=0}=
=P{X
1
=0}P{X
2
=0}, P{X
1
=0,X
2
=1}=
=P{X
1
=0}P{X
2
=1}, P{X
1
=1,X
2
=0}=
