已知2sin(x+2y-3z)=x+2y03z,则
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解析:记F(x,y,z)=2sin(x+2y-3z)-x-2y+3z,则 F x (x,y,z)=2cos(x+2y-3z)-1,F y (x,y,z)=4cos(x+2y-3z)-2, F z (z,y,z)=-6cos(x+2y-3z)+3,所以