单选题ATM是一种面向连接的快速分组交换技术，数据以定长的信元为单位进行传输，下面正确的叙述为 (28) 。

单选题数据存储在磁盘上的排列方式会影响I/O服务的总时间。假设每磁道划分成10个物理块，每块存放1个逻辑记录。逻辑记录R1，R2，…，R10存放在同一个磁道上，记录的安排顺序如下表所示： 物理块 1 2 3 4 5 6 7 8 9 10 逻辑记录 R1 R2 R3 R4 R5 R6 R7 R8 R9 R10 假定磁盘的旋转速度为20ms/周，磁头当前处在R1的开始处。若系统顺序处理这些记录，使用单缓冲区，每个记录处理时间为4ms，则处理这10个记录的最长时间为 (9) ； 若对信息存储进行优化分布后，处理10个记录的最少时间为 (10) 。

单选题双层双面的只读DVD盘片的存储容量可以达到 。

单选题《中华人民共和国著作权法》中，著作权与下列哪一项系同一概念 (4) 。按照《中华人民共和国著作权法》的权利保护期规定，下列权项中，受到永久保护的是 (5) 。下列选项中不属于《中华人民共和国著作权法》所保护的作品是 (6) 。《中华人民共和国著作权法》所称的发表的含义是指将作品 (7) 。

单选题Observe that for the programmer, as for the chef, the urgency of the patron (顾客) may govern the scheduled completion of the task, but it cannot govern the actual completion. An omelette (煎鸡蛋) , promised in two minutes, may appear to be progressing nicely. But when it has not set in two minutes, the customer has two choices-waits or eats it raw. Software customers have had (71) choices. Now I do not think software (72) have less inherent courage and firmness than chefs, nor than other engineering managers. But false (73) to match the patron's desired date is much more common in our discipline than elsewhere in engineering. It is very (74) to make a vigorous, plausible, and job risking defense of an estimate that is derived by no quantitative method, supported by little data, and certified chiefly by the hunches of the managers. Clearly two solutions are needed. We need to develop and publicize productivity figures, bug-incidence figures, estimating rules, and so on. The whole profession can only profit from (75) such data. Until estimating is on a sounder basis, individual managers will need to stiffen their backbones and defend their estimates with the assurance that their poor hunches are better than wish derived estimates.

单选题It should go without saying that the focus of UML is modeling. However, what that means, exactly, can be an open-ended question. (71) is a means to capture ideas, relationships, decisions, and requirements in a well-defined notation that can be applied to many different domains. Modeling not only means different things to different people, but also it can use different pieces of UML depending on what you are trying to convey. In general, a UML model is made up of one or more (72) . A diagram graphically represents things, and the relationships between these things. These (73) can be representations of real-world objects, pure software constructs, or a description of the behavior of some other objects. It is common for an individual thing to show up on multiple diagrams; each diagram represents a particular interest, or view, of the thing being modeled. UML 2.0 divides diagrams into two categories: structural diagrams and behavioral diagrams. (74) are u sed to capture the physical organization of the things in your system, i.e., how one object relates to another. (75) focus on the behavior of elements in a system. For example, you can use behavioral diagrams to capture requirements, operations, and internal state changes for elements.

单选题MPEG-1的视频图像序列由帧内图像、预测图像和 (115) 构成，其中 (116) 的数据量最少。MPEG-1视频编码的运动补偿是基于 (117) 的宏块进行的，图像的DCT编码是在 (118) 颜色空间进行的。

单选题计算机内存一般分为静态数据区、代码区、栈区和堆区，若某指令的操作数之一采用立即数寻址方式，则该操作数位于 。 A．静态数据区 B．代码区 C．栈区 D．堆区

单选题一幅256色的图像，其像素深度为 位。 A．3 B．8 C．16 D．256

单选题设连通图G中的边集E＝(a，b)，(a，e)，(a，c)，(b，e)，(e，d)，(d，f)，(f，c)，则从顶点a出发可以得到一种深度优先遍历的顶点序列为______。 A．abedfc B．acfebd C．abcedf D．abcdef

单选题以下的采样频率中哪个是目前音频卡所支持的。

单选题小王购买了一个“海之久”牌活动硬盘，而且该活动硬盘还包含有一项实用新型专利， 那么，小王享有 。

单选题以下软件产品中，用于绘制三维动画模型的工具软件是 。

单选题在数据库系统中，数据的完整性约束的建立需要通过数据库管理系统提供的数据 语言来实现。 A．定义 B．操作 C．查询 D．控制

单选题个人电脑通常支持使用32位真彩色显示模式，其中R、G、B分量各占 位。

单选题在函数的相互调用过程中，主调函数中的实参和被调函数中的形参______。 A．个数、次序必须相同，但数据类型可以不考虑 B．个数、次序和对应参数的数据类型都应该相同 C．个数、次序和数据类型均可以不相同 D．对应参数数据类型应相同，但个数和次序可以不考虑

单选题用于静态图像压缩的国际标准算法是 (8) 。 A．MPEG B．H.261 C．YIQ D．JPEG

单选题若采用邻接矩阵来存储简单有向图，则其某一个顶点i的入度等于该矩阵 (20) 。

单选题在指令系统的各种寻址方式中，获取操作数最快的方式是 (36) 。若操作数的地址包含在指令中，则属于 (37) 方式。