Nitrogen oxides（NO<sub>2</sub> and NO）are absorbed by tributyl phosphorate（TBP）to fom a new complex mixture of TBP-NO<sub>x</sub>. which is used as a selective oddizing agent to oxidize ben...Nitrogen oxides（NO<sub>2</sub> and NO）are absorbed by tributyl phosphorate（TBP）to fom a new complex mixture of TBP-NO<sub>x</sub>. which is used as a selective oddizing agent to oxidize benzylalcohols to corresponding sldehydes or ketones In high yield. In the reaction process, nitrogen oxides are llberated mildly and mainly reduced to nitrogen, while tributyl phosphorate is recovered end recycled.展开更多
一本杂志上刊登过如下一道题目: 题一:设,f（x）=（x<sup>2</sup>-4）<sup>1/2</sup>（x≤-2）.（1）求f<sup>-1</sup>（x）;（2）设a<sub>1</sub>=1,a<sub>n</sub>=f<...一本杂志上刊登过如下一道题目: 题一:设,f（x）=（x<sup>2</sup>-4）<sup>1/2</sup>（x≤-2）.（1）求f<sup>-1</sup>（x）;（2）设a<sub>1</sub>=1,a<sub>n</sub>=f<sup>-1</sup>(a<sub>n-1</sub>)（n≥2,n∈N）,求a<sub>n</sub>;（3）求sum from i=1 to n 1/（a<sub>1</sub>+a<sub>i</sub>+1）的值该题作为函数与数列的综合题在教学中广为流传,通常简解如下解:（1）函数,f（x）=（x<sup>2</sup>-4）<sup>1/2</sup>（定义域为x≤—2,值域为y≥0）的反函数为f<sup>-1</sup>（x）=-（x<sup>2</sup>+4）<sup>1/2</sup>（定义域为x≥0,值域为y≤-2） （2）∵a<sub>1</sub>=1,a<sub>n</sub>=f<sup>-1</sup>(a<sub>n-1</sub>)由迭代法得:a<sub>n</sub>=-(a<sub>n-1</sub><sup>2</sup>+4)<sup>1/2</sup>=-(a<sub>n-2</sub><sup>2</sup>+2×4)<sup>1/2</sup>=…=-（a<sub>1</sub><sup>2</sup>+（n-1）4）<sup>1/2</sup>=-（4n-3）<sup>1/2</sup>(亦可由a<sub>n</sub><sup>2</sup>=a<sub>n-1</sub><sup>2</sup>+4,n=2,3,…n,累加而得) （3） 注意到 a<sub>n</sub><sup>2</sup>-a<sub>n-1</sub><sup>2</sup>=4,展开更多
A series of material ejections associated with flares are observed in AR 5395 during 8 to 19 March, 1989. five events selected are repoted in this paper.
文摘Nitrogen oxides（NO<sub>2</sub> and NO）are absorbed by tributyl phosphorate（TBP）to fom a new complex mixture of TBP-NO<sub>x</sub>. which is used as a selective oddizing agent to oxidize benzylalcohols to corresponding sldehydes or ketones In high yield. In the reaction process, nitrogen oxides are llberated mildly and mainly reduced to nitrogen, while tributyl phosphorate is recovered end recycled.
文摘一本杂志上刊登过如下一道题目: 题一:设,f（x）=（x<sup>2</sup>-4）<sup>1/2</sup>（x≤-2）.（1）求f<sup>-1</sup>（x）;（2）设a<sub>1</sub>=1,a<sub>n</sub>=f<sup>-1</sup>(a<sub>n-1</sub>)（n≥2,n∈N）,求a<sub>n</sub>;（3）求sum from i=1 to n 1/（a<sub>1</sub>+a<sub>i</sub>+1）的值该题作为函数与数列的综合题在教学中广为流传,通常简解如下解:（1）函数,f（x）=（x<sup>2</sup>-4）<sup>1/2</sup>（定义域为x≤—2,值域为y≥0）的反函数为f<sup>-1</sup>（x）=-（x<sup>2</sup>+4）<sup>1/2</sup>（定义域为x≥0,值域为y≤-2） （2）∵a<sub>1</sub>=1,a<sub>n</sub>=f<sup>-1</sup>(a<sub>n-1</sub>)由迭代法得:a<sub>n</sub>=-(a<sub>n-1</sub><sup>2</sup>+4)<sup>1/2</sup>=-(a<sub>n-2</sub><sup>2</sup>+2×4)<sup>1/2</sup>=…=-（a<sub>1</sub><sup>2</sup>+（n-1）4）<sup>1/2</sup>=-（4n-3）<sup>1/2</sup>(亦可由a<sub>n</sub><sup>2</sup>=a<sub>n-1</sub><sup>2</sup>+4,n=2,3,…n,累加而得) （3） 注意到 a<sub>n</sub><sup>2</sup>-a<sub>n-1</sub><sup>2</sup>=4,
文摘A series of material ejections associated with flares are observed in AR 5395 during 8 to 19 March, 1989. five events selected are repoted in this paper.
